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Energy required to dissociate 4g of gase...

Energy required to dissociate `4g` of gaseous hydrogen into free gaseous atoms is `208Kcal` at `25^(@)C`
The bond energy of `H-H` bond will be

A

1.04 Kcal

B

10.4 Kcal

C

104 Kcal

D

1040 Kcal

Text Solution

Verified by Experts

The correct Answer is:
C
`H-H_((g))rarr 2H_((g)) , Delta H = ?`
Energy required to dissociate `4g H_(2)` is 208 KCal.
`therefore` Energy required to dissociate 1 mole (2g) is
`(208)/(4)xx2=104 KCal mol^(-1)`
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