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Find Power set of the set A={phi,{phi}}....

Find Power set of the set `A={phi,{phi}}`.

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To find the power set of the set \( A = \{\phi, \{\phi\}\} \), we will follow these steps: ### Step 1: Understand the Definition of Power Set The power set of a set \( S \) is the set of all possible subsets of \( S \), including the empty set and \( S \) itself. **Hint:** Remember that the power set includes all combinations of elements, including no elements at all (the empty set). ### Step 2: Identify the Elements of Set \( A \) The set \( A \) has two elements: 1. The empty set \( \phi \) 2. The set containing the empty set \( \{\phi\} \) **Hint:** List out the elements clearly to avoid confusion when forming subsets. ### Step 3: List All Possible Subsets of \( A \) Now we will list all possible subsets of \( A \): 1. The empty set: \( \emptyset \) 2. The subset containing just the first element: \( \{\phi\} \) 3. The subset containing just the second element: \( \{\{\phi\}\} \) 4. The subset containing both elements: \( \{\phi, \{\phi\}\} \) **Hint:** For each element in the set, decide whether to include it in a subset or not. ### Step 4: Compile the Power Set Now we can compile all the subsets we found into the power set \( P(A) \): \[ P(A) = \{\emptyset, \{\phi\}, \{\{\phi\}\}, \{\phi, \{\phi\}\}\} \] **Hint:** Ensure that you have included all possible combinations of the elements. ### Final Answer Thus, the power set of the set \( A = \{\phi, \{\phi\}\} \) is: \[ P(A) = \{\emptyset, \{\phi\}, \{\{\phi\}\}, \{\phi, \{\phi\}\}\} \]
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Knowledge Check

  • The maximum number of equivalence relations on the set A = {phi , {phi}, {{phi}}} are

    A
    1
    B
    2
    C
    3
    D
    5
  • The set phi is :

    A
    null set
    B
    U
    C
    U
    D
    None of these.
  • Let A = {phi, {phi}, {phi, {phi}}}, B = {{phi}, { {phi}}} . If m denotes the number of elements in power set of A and n denotes the number of elements in power set of B, then 2log_(n)m has the value equal to -

    A
    1
    B
    2
    C
    3
    D
    4
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