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If (m + 2) sintheta + (2m-1) costheta = ...

If `(m + 2) sintheta + (2m-1) costheta = 2m+1`, then

A

`tantheta=(3)/(4)`

B

`tantheta=(2m)/(m^(2)+1)`

C

`tantheta=(2m)/(m^(2)-1)`

D

`tantheta=(4)/(3)`

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The correct Answer is:
C, D
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RESONANCE-FUNDAMENTAL OF MATHEMATICS-Exercise
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