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If the angles of elevation of the top of tower from three collinear points `A`, `B` and `C`, on a line leading to the foot of the tower, are `30^(@)`, `45^(@)` and `60^(@)` respectively, then the ratio , `AB : BC` is

A

`sqrt(3) : 1`

B

`sqrt(3) : sqrt(2)`

C

`1 : sqrt(3)`

D

`2 : 3`

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The correct Answer is:
To solve the problem of finding the ratio \( AB : BC \) given the angles of elevation from points \( A \), \( B \), and \( C \) to the top of a tower, we can follow these steps: ### Step 1: Draw the Diagram Draw a vertical tower \( OT \) where \( O \) is the foot of the tower and \( T \) is the top. Mark the points \( A \), \( B \), and \( C \) on the ground such that they are collinear and leading towards the tower. Label the angles of elevation from these points: - Angle at \( C \) (60°) - Angle at \( B \) (45°) - Angle at \( A \) (30°) ### Step 2: Set Up the Relationships Using Trigonometry Using the tangent function, we can express the height of the tower \( H \) in terms of the distances from the foot of the tower to each point: 1. From point \( C \): \[ \tan(60^\circ) = \frac{H}{OC} \implies H = OC \cdot \sqrt{3} \] 2. From point \( B \): \[ \tan(45^\circ) = \frac{H}{OB} \implies H = OB \implies H = OC + BC \] 3. From point \( A \): \[ \tan(30^\circ) = \frac{H}{OA} \implies H = OA \cdot \frac{1}{\sqrt{3}} \implies H = OC + BC + AB \cdot \frac{1}{\sqrt{3}} \] ### Step 3: Substitute and Rearrange Now we have three equations for \( H \): 1. \( H = OC \cdot \sqrt{3} \) 2. \( H = OC + BC \) 3. \( H = OC + BC + AB \cdot \frac{1}{\sqrt{3}} \) ### Step 4: Equate the Expressions for \( H \) From the first two equations: \[ OC \cdot \sqrt{3} = OC + BC \] Rearranging gives: \[ OC(\sqrt{3} - 1) = BC \quad \text{(1)} \] From the second and third equations: \[ OC + BC = OC + BC + AB \cdot \frac{1}{\sqrt{3}} \] This simplifies to: \[ 0 = AB \cdot \frac{1}{\sqrt{3}} \quad \text{(2)} \] ### Step 5: Solve for \( AB \) and \( BC \) From equation (1): \[ BC = OC(\sqrt{3} - 1) \] From equation (2), we can express \( AB \) in terms of \( BC \): \[ AB = BC \cdot \left(\sqrt{3} - 1\right) \] ### Step 6: Find the Ratio \( AB : BC \) Now we can find the ratio: \[ \frac{AB}{BC} = \frac{BC \cdot \left(\sqrt{3} - 1\right)}{BC} = \sqrt{3} - 1 \] Thus, the ratio \( AB : BC \) is: \[ AB : BC = \sqrt{3} : 1 \] ### Final Answer The required ratio \( AB : BC \) is \( \sqrt{3} : 1 \). ---
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