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H2 S will precipitate the sulphide of al...

`H_2 S` will precipitate the sulphide of all the metals from the solution of chlorides of Cu, Zn and Cd if

A

The solution is aqueous

B

the solution is acidic

C

the solution is dilute acidic

D

none of the above solution is present

Text Solution

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Sulphides of Cu, Zn and Cd will be precipitated as if the solution is aqueous i.e., it does not contain any acid.
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Consider the following statement: S_(1) : Cu^(2+) ions are reduced to Cu^(+) by potassium iodide and potassium cyanide both, when taken in excess S_(2) : H_(2)S will precipitate the sulphide of all the metals from the solutions of chlorides of Cu,Zn and Cd if the solution is aqueous. S_(3) :The presence of magnesium is confirmed in qualitative analysis by the formation of a white crystal S_(4) :Calomel on reaction with potassium iodide gives red precipitate. and arrange in the order of true/false.

Consider the following statements: Statement-1: Cu^(2+) ions are reduced to Cu^(+) by potassium iodide and potassium cyanide both, when taken in excess. Statement-2: H_(2)S will precipitate the sulphide of all the metals from the solution from the solutions of chlorides of Cu,Zn and Cd if the solution is aqueous. Statement-3: The presence of magnesium is confirmed in qualitative analysis by the formation of a white crystalline precipitate of MgNH_(4)PO_(4) . Statement-4: Calmol on reaction with potassium iodide gives red precipitate.

Arrange the following metals in the order in whiCHM they displace eaCHM other from the solution of their salts. Al, Cu, Fe, Mg, and Zn .