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$ Addition of NH(4)OH to an aqueous solu...

$ Addition of `NH_(4)OH` to an aqueous solution of `BaCl_(2)` in the presence of `NH_(4)Cl` (excess) precipitates `Ba(OH)_(2)`.
! `Ba(OH)_(2)` is insoluble in water.

A

Both A and R are true and R is the correct explanation of A

B

Both A and R are true but R is not a correct explanation of A

C

A is true but R is false

D

A is false but R is true.

Text Solution

Verified by Experts

Addition of `NH_(4)OH` to an aqueous solution of `BaCl_2` in the presence `NH_(4)Cl` (excess) does not give a precipitate of `Ba(OH)_(2)` as `Ba(OH)_2` is soluble in water.
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Assertion (A): Addtion of nH_(4)OH to an aqueous solution of BaCl_(2) in the presence of excess of NH_(4)Cl precipitates Ba(OH)_(2) . Reason (R ): Ba(OH)_(2) is insoluble in water.

Statement-1 :Addition of NH_(4)OH to an aqueous solution of BaCl_(2) in presence of NH_(4)Cl (excess) precipitates Ba(OH)_(2) . Statement-2: Ba(OH)_(2) is water soluble.

When NH_(4)Cl is added to a solution of NH_(4)OH :

When NH_(4)Cl is added to a solution of NH_(4)OH :

Magnesium is not precipitated from a solution of its salt by NH_(4)OH in the presence of NH_(4)CI. Explain.

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