Sulphuric acid is not for the preparation of original solution in analysing basic radicals because

Options

A. it is a reducing agent
B. it forms insoluble sulphate
C. it forms a soluble complex
D. it is viscous in nature

Explanation

It may form insoluble sulphates with certain basic radicals such as `Pb^(2+),Ba^(2+),Ca^(2+)` etc.