A coil of `Cu` wire (radius `r`, self-inductance `L`) is bent in two concentric turns each having radius `(r )/(2)`. The self-inductance now

Self inductance || L-R Circuit

A wire of fixed length is wound on a solenoid of length l and radius r, its self inductance is found to be L. If same wire is wound on a solenoid of length l/3 and radius r/3 , then self inductance will be

If number of turns in a coil is quadrupled, then self-inductance will be:

The self-inductance of a solenoid is L. If it is cut into two equal halves, what will be the self-inductance of each half?

How does self inductance of a coil depend on number of turns in the coil?

How the self-inductance of a coil depends on number of turns in the coil ?

A solenoid having 500 turns and length 2 m has radius of 2 cm , the self inductance of solenoid

A wire of fixed length is wound on a solenoid of length l and radius r . Its self-inductance is found to be L . Now, if the same wire is wound on a solenoid of length l//2 and radius r//2 then the self-inductance will be

A wire of fixed length is wound on a solenoid of length l and redius r . Its self-inductance is found to be L . Now, if the same wire is wound on a solenoid of length l//2 and redius r//2 then the self-inductance will be