A golfer standing on level ground hits a ball with a velocity of `52 m s^-1` at an angle `theta` above the horizontal. If `tan theta = 5//12`, then find the time for which then ball is atleast `15 m` above the ground `(take g = 10 m s^-2)`.

A golfer standing on level ground hits a ball with a velocity of u=50ms^(-1) at an angle theta above the horizontal.If tan theta=(5)/(12) then the time for which the ball is at least 15m above the ground will be take g=10ms^(-2)

A golfer standing on the ground hits a ball with a velocity of 52 m//s at an angle theta above the horizontal if tan theta=5/12 find the time for which the ball is at least 15m above the ground? (g=10m//s^(2))

A golfer standing on the ground hits a ball with a velocity of 52 m//s at an angle theta above the horizontal if tan theta=5/12 find the time for which the ball is at least 15m above the ground? (g=10m//s^(2))

A golfer standing on the ground hits a ball with a velocity of 52 mis at an angle Q above the 5 horizontal if tan theta = 5/12 find the time for which the ball is LB at least 15m above the ground? (g = m//s^(2) )

A golfer standing on level ground hits a ball with a velocity of u=52m//s at an angle alpha above the horizontal. If tantheta=5//12 , then the time interval for which the ball is at least 15 m above the ground (i.e. between A and B will be :(take g=10m//s^(2) )

A golfer standing on level ground hits a ball with a velocity of u=52m//s at an angle alpha above the horizontal. If tantheta=5//12 , then the time interval for which the ball is at least 15 m above the ground (i.e. between A and B will be :(take g=10m//s^(2) )

A boy throws a ball with a velocity of 15 m/s at an angle of 15° with the horizontal. The distance at which the ball strikes the ground is