A string 50 cm long is under a tension of 20N force. Caculate the frequency of fundamental mode given that mass of the string is 1 g.

The mass of 1m long steel wire is 20 g. The wire is stretched under a tension of 800N. What are the frequencies of fundamental mode of vibration and next two higher modes ?

A string 1 m long with mass 0.1 g cm^(-1) is under a tension of 400 N.Find is fundamental frequency of vibration.

A fundamental tone of frequency n_(1) is produced when a string stretched at both ends is vibrated. The frequency of the fundamental tone changes to n_(2) when the tension in the string is double. What is the ratio of n_(1) and n_(2) ?

A string under a tension of 100 N , emitting its fundamental mode , gives 5 beats//s with a tuning fork. When the tension is increased to 121 N , again 5 beats//s are heard. The frequency of the fork is

A string under a tension of 100 N , emitting its fundamental mode , gives 5 beats//s with a tuning fork. When the tension is increased to 121 N , again 5 beats//s are heard. The frequency of the fork is

A string under a tension of 100 N , emitting its fundamental mode , gives 5 beats//s with a tuning fork. When the tension is increased to 121 N , again 5 beats//s are heard. The frequency of the fork is

A string 50 cm long and weighing 1.0 g produces a note of 100 Hz on plucking in the middle.What is the tension in the string ?