On analysing an impure sample of sodium chloride, the percentage of chlorine was found to be 45.5. What is the percentage of pure sodium chloride in the sample ?

Explanation

Molar mass of pure NaCl=Atomic mass of Na+Atomic of Cl
=23+35.5=58.5u
`"Percentage of chlorine in pure of NaCl"=((35.5u))/((58.5u))xx100=60.6%`
Now, If the chlorine is 60.6 parts, NaCl=100parts
if chlorine is 45.5 parts, NaCl`=((45.5u))/((60.6u))xx100=75%`
Thus, percentage of pure NaCl=75%