Calculate the weight of carbon monoxide having the same number of oxygen atoms as are present in 22g of carbon dioxide

Explanation

Step -1 No.of oxygen atoms in 22g of carbonate dioxide `(CO_(2))`
Molar mass of `CO_(2)=12+2xx16=44g`
44g of `CO_(2)` represent =1 mol
22g of `CO_(2)` represent =`1"mol"xx(22g)/(44g)=0.5"mol"`
Now, 1 mole of `CO_(2)` containg oxygen atoms `2xxN_(0)=2xx6.022xx10^(23)`
`"0.5 mole of "CO_(2)" containg oxygen atoms"=2xx6.022xx10^(23)=6.022xx10^(23)`
Step-II Weights of carbon monoxide (CO)
`6.022xx10^(23)` molecules of CO have mass=Molar mass of CO=`12+16=28g`