Calculate the molecular masses of `H_(2), O_(2), Cl_(2), CO_(2), CH_(4), C_(2)H_(6), C_(2)H_(4), NH_(3), CH_(3)OH`.

Explanation

(i)Hydrogen `(H_(2))`
`"Molecular mass of "H_(2)=2xx "Atomic mass of H"=(2xx1u)=2u`
(ii)Oxygen `(O_(2))`
`"Molecular mass of "O_(2)=2xx "Atomic mass of O"=(2xx16u)=32u`
(iii)Chlorine `(Cl_(2))`
`"Molecular mass of "Cl_(2)=2xx "Atomic mass of Cl"=(2xx35.5u)=71u`
(iv)Carbon dioxde `(CO_(2))`
`"Molecular mass of "CO_(2)=(1xx "Atomic mass of C")+(2xx "Atomic mass of O")`
`1xx12u)+(2xx16u)=12u+32u=44u`.
(v)Methane `(CH_(4))`
`"Molecular mass of "CH_(4)=(1xx "Atomic mass of C")+(4xx "Atomic mass of H")`
`=(1xx12u)+(4xx1u)=30u`
(vii) Ethylene `(C_(2)H_(4))`
`"Molecular mass of "C_(2)H_(4)=(2xx "Atomic mass of C")+(6xx "Atomic mass of H")`
`=(2xx12u)+(6xx1u)=30u`
(viii)Ethylene `(C_(2)H_(4))`
`"Molecular mass of "C_(2)H_(4)=(2xx "Atomic mass of C")+(4xx "Atomic mass of H")`
`(2xx12u)+(4xx1u)=28u`.
(viii)Ammonia `(NH_(3))`
`"Molecular mass of "NH_(3)=(1xx "Atomic mass of N")+(3xx "Atomic mass of H")`
`=(1xx14u)+(3xx1u)=17u`
(ix) Methyl alcohol `(CH_(3)OH)`
`"Molecular mass of "CH_(3)COOH=(1xx "Atomic mass of C")+(4xx "Atomic mass of H")+(1xx"Atomic mass of O")`
`=(1xx12u)+(4xx1u)+(1xx16u)=32u`