In photosynthesis, 6 molecules of carbon combine with an equal number of water molecules through a complex series of reactions to give a molecule of glucose having a molecular formula `C_(6)H_(12)O_(6)`. How many grams of water would be requried to produce 18g of glucose? Compute the volume of water so consumed assuming the density of water to be `1g cm^(-3)`.

Explanation

The chemical reaction involved is:
`6CO_(2)+underset((6xx18g))(6H_(2)O) underset("Sunlight")overset("Chlorophyll")to underset((180g))(C_(6)H_(12)O_(6))+6O_(2)`
To produce 180g of glucose, mass of water consumed=108g
To produce 18g of glucose, mass of water consumed=`=((108g))/((180g))xx(18g)=10.8g`
`"Density of water"=1"g cm"^(-3)`
`"Volume of water"=("Mass of water")/("Density of water")=((10.8g))/((1"g cm"^(-3)))=10.8cccm^(3)`