`|x^2-5x|<6`

Compute lim_(x to infty)(x^(2)+5x+2)/(2x^(2)-5x+1)

Factorise: 3(x^2-5x)^2-2(x^2-5x+5)-6

Compute {:(" Lt"),(xrarroo):}(x^(2)+5x+2)/(2x^(2)-5x+1)

Find Lt_(xtooo)(x^(2)+5x+2)/(2x^(2)-5x+1)

The range of the function f(x)=log_(3)((x^(2)-5x+6)/(x^(2)-5x+4)) is

Solve the following equations. (x^2 - 5x)^2 - 7 (x^2-5x) div 6=0 .

Solve the following: (sqrt(x^2-5x+6)+sqrt(x^2-5x+4))^(x/2)+(sqrt(x^2-5x+6) - sqrt(x^2-5x+4))^(x//2)=2^((x+4)/4)

Solve the following: (sqrt(x^(2)-5x+6)+sqrt(x^(2)-5x+4))^((x)/(2))+(sqrt(x^(2)-5x+6)-sqrt(x^(2)-5x+4))^(x/2)=2^((x+4)/(4))