The vibration of a string fixed at both ends are described by `Y= 2 sin (pi x) sin (100 pit)` where Y is in mm, x is in cm, t in sec then

The vibrations of a string fixed at both ends are represented by y = 16 sin (pi x/15) cos 96 pi t where x and y are in cm and t in seconds. Then the phase difference between the points at x = 13 cm and X = 16 cm in radian is

The vibrations of a string fixed at both ends are represented by y = 16 sin 15 pi x cos 96 pi t where x and y are in cm and t in seconds. Then the phase difference between the points at x = 13 cm and X = 16 cm in radian is

The vibrations of a string fixed at both ends are represented by y=16sin((pix)/(15))cos(96pit) . Where 'x' and 'y' are in cm and 't' in seconds. Then the phase difference between the points at x=13cm and x=16 in radian is

The displacement of a string fixed at both the ends is given by y= 0.8 sin ((pi x)/(3)) cos (60 pi t) where y and x in metres and t is in second. What is the wavelength and frequency of the two interfering waves ?

The equation of a vibrating string, fixed at both ends, is given by y = (3 mm) sin ((Pix)/(15))sin (400 Pit) where x is the distance (in cm) measured from one end of the string, t is the time (in seconds), and y gives the displacement. The string vibrates in 4 loops. The speed of transverse waves along the string equals, for the fundamental mode,

The Equation for the vibration of a string fixed at both ends vibrating in its third harmonic is given by y = 2 sin (0.6x) cos (500 pi t) (x, y are in cm t is in sec). The length of the string is

The vibrations of a string of length 60 cm fixed at both ends are represented by the equation y=4 sin (pix//15) cos (96 pit) where x and y are in cm and t in seconds. The maximum displacement at x = 5 cm is–

The transverse displacement of a string fixed at both ends is given by y=0.06sin((2pix)/(3))cos(100pit) where x and y are in metres and t is in seconds. The length of the string is 1.5 m and its mass is 3.0xx10^(-2)kg . What is the tension in the string?