Given that `y=(3x^(2)+7)(6x+3).` Find `(dy)/(dx).`
Note : This problem can be solved by using Theorm 5.
Here `u=3x^(2)+7 and v=6x+3.`

Explanation

To find the derivative \(\frac{dy}{dx}\) of the function \(y = (3x^2 + 7)(6x + 3)\), we can use the product rule of differentiation. The product rule states that if \(y = u \cdot v\), then:

\[ \frac{dy}{dx} = u \frac{dv}{dx} + v \frac{du}{dx} \]

where \(u = 3x^2 + 7\) and \(v = 6x + 3\).

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