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Find the logarithm of the following numb...

Find the logarithm of the following number :
(v) 0.5438

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To find the logarithm of the number 0.5438, we can follow these steps: ### Step 1: Rewrite the number in scientific notation We can express 0.5438 as: \[ 0.5438 = 5.438 \times 10^{-1} \] ### Step 2: Apply the logarithm property Using the property of logarithms that states \(\log(ab) = \log(a) + \log(b)\), we can write: \[ \log(0.5438) = \log(5.438 \times 10^{-1}) = \log(5.438) + \log(10^{-1}) \] ### Step 3: Calculate \(\log(10^{-1})\) We know that: \[ \log(10^{-1}) = -1 \] ### Step 4: Find \(\log(5.438)\) using a logarithm table From the logarithm table, we find: \[ \log(5.438) \approx 0.735 \] ### Step 5: Combine the results Now substituting the values we have: \[ \log(0.5438) = \log(5.438) + \log(10^{-1}) = 0.735 - 1 \] \[ \log(0.5438) = 0.735 - 1 = -0.265 \] ### Final Answer Thus, the logarithm of 0.5438 is: \[ \log(0.5438) \approx -0.265 \] ---

To find the logarithm of the number 0.5438, we can follow these steps: ### Step 1: Rewrite the number in scientific notation We can express 0.5438 as: \[ 0.5438 = 5.438 \times 10^{-1} \] ...
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