Obtain the differential coefficient of the following:
`(logx)/(1+logx)`

Explanation

To find the differential coefficient of the function \( y = \frac{\log x}{1 + \log x} \), we will use the quotient rule for differentiation. The quotient rule states that if you have a function in the form \( \frac{u}{v} \), then its derivative is given by:

\[ \frac{dy}{dx} = \frac{v \frac{du}{dx} - u \frac{dv}{dx}}{v^2} \]

where \( u = \log x \) and \( v = 1 + \log x \).

...