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If the size of the nucleus ( in the rang...

If the size of the nucleus ( in the range of `10^(-15)" to "10^(-14)m`) is scaled upto the tip of a sharp pin `(approx 10^(-5) m)`, what roughly is the size of the atom? Assume tip of the pin to be in the range `10^(5)m " to "10^(-4)m`.

Text Solution

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Magnification `=("Size of the tip of sharp pin")/("Size of nucleus")`
`=(10^(-5))/(10^(-15))=10^(10)`
We know that, actual size of atom `= dot(A)=10^(-10)m`
This is now scaled upto a factor of `10^(10)`
Apparent size of atom `=10^(-10)xx10^(10)=1m`
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