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Two resistances of values 150 pm 2 Omega...

Two resistances of values `150 pm 2 Omega" and "250 pm 5 Omega` are connected in series. Find their equivalent resistance.

Text Solution

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Given, `R_(1)= 150 pm 2 Omega, R_(2)-250 pm 5 Omega`
Equivalent resistance
`R= R_(1)+R_(2)= (150+250)pm (2+5)`
`=(400 pm 7) Omega`.
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