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The resistance R= (V)/(I), where V= (100...

The resistance `R= (V)/(I)`, where `V= (100+-5.0) V` and `I=(10+-0.2)A`. Find the percentage error in `R`.

Text Solution

Verified by Experts

Percentage error in `V= (5)/(100)xx100= 5%`
Percentage error in `I= (0.2)/(10)xx100=2%`
`R=(V)/(I)`
`(triangleR)/(R )xx100= (triangleV)/(V)xx100+(triangleI)/(I)xx100`
Total percentage error in R is
`(triangleR)/(R )xx100= 5%+2%=7%`
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