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The rotational K.E. of a body is given b...

The rotational K.E. of a body is given by `(1)/(2) I omega^2.` Use this equation to obtain the dimensions of I.

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`I= [ML^2]`
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Moment of inertia of a body about a given axis is the rotational inertia of the body about that axis. It is respresented by I = MK^(2) , where M is mass of body and K is radius of gyration of the body about that axis. It is a scalar quantity, which is measured in kg m^(2) . when a body rotates about a given axis, and teh axis of rotates also moves, then total K.E. of body = K.E. of translation + K.E. of rotation E = (1)/(2)mv^(2) + (1)/(2)I omega^(2) Which the help of the compreshension given above, choose the most apporpriate altermative for each of the following questions : Kinetic energy of rotation of the flywheel in the above case is

Moment of inertia of a body about a given axis is the rotational inertia of the body about that axis. It is respresented by I = MK^(2) , where M is mass of body and K is radius of gyration of the body about that axis. It is a scalar quantity, which is measured in kg m^(2) . when a body rotates about a given axis, and teh axis of rotates also moves, then total K.E. of body = K.E. of translation + K.E. of rotation E = (1)/(2)mv^(2) + (1)/(2)I omega^(2) Which the help of the compreshension given above, choose the most apporpriate altermative for each of the following questions : Moment of inertia of a body depends on (i) mass of body (ii) size and shape of body (iii) axis of rotation of body (iv) all the above

Moment of inertia of a body about a given axis is the rotational inertia of the body about that axis. It is respresented by I = MK^(2) , where M is mass of body and K is radius of gyration of the body about that axis. It is a scalar quantity, which is measured in kg m^(2) . when a body rotates about a given axis, and teh axis of rotates also moves, then total K.E. of body = K.E. of translation + K.E. of rotation E = (1)/(2)mv^(2) + (1)/(2)I omega^(2) Which the help of the compreshension given above, choose the most apporpriate altermative for each of the following questions : A circular disc and a circular ring of same mass and same diameter have, about a given axis,

Moment of inertia of a body about a given axis is the rotational inertia of the body about that axis. It is respresented by I = MK^(2) , where M is mass of body and K is radius of gyration of the body about that axis. It is a scalar quantity, which is measured in kg m^(2) . when a body rotates about a given axis, and teh axis of rotates also moves, then total K.E. of body = K.E. of translation + K.E. of rotation E = (1)/(2)mv^(2) + (1)/(2)I omega^(2) Which the help of the compreshension given above, choose the most apporpriate altermative for each of the following questions : A 40 kg flywheel in the from of a unifrom circular disc of diameter 1 m is making 120 rpm . Its moment of inertia about a transverse axis through its centre is

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The linear velocity of a rotating body is given by vec(v)= vec(omega)xxvec(r ) , where vec(omega) is the angular velocity and vec(r ) is the radius vector. The angular velocity of a body is vec(omega)= hat(i)-2hat(j)+2hat(k) and the radius vector vec(r )= 4hat(j)-3hat(k) , then |vec(v)| is

The linear velocity of a rotating body is given by vec(v)=vec(omega)xxvec(r) , where vec(omega) is the angular velocity and vec(r) is the radius vector. The angular velocity of a body is vec(omega)=hat(i)-2hat(j)+2hat(k) and the radius vector vec(r)=4hat(j)-3hat(k) , then |vec(v)| is-

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