The length breadth and thickness of a metal sheet are 4.234 m 1.005 m and 2.01 cm respectively. Given the area and volume of the sheet to correct number of significant figure.

Explanation

Length (l)= 4.234m, Breadth (b)= 1.005m, Thickness (t)= 0.0201m
Area `=2(lb+bt+tl)`
`=2(4.234xx1.005+1.005xx0.0201+0.0201xx4.234)`
`=2[4.255+0.2011+0.0889]`
As area can contain maximum of three significant figures
Area `=8.73 m^(2)`
Volume of the sheet `=l xx b xx t`
`=4.234xx1.005xx0.0201= 0.0855m^(3)`
As volume can also contain maximum of three significant figures
Volume `=0.0855m^(3)`.