What is the dimensional formula of elect...

What is the dimensional formula of electric permittivity of free space?

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To find the dimensional formula of electric permittivity of free space (ε₀), we can start from the formula for the electrostatic force between two point charges. The formula is given by: \[ F = \frac{1}{4\pi \epsilon_0} \frac{q_1 q_2}{r^2} \] Where: - \( F \) is the electrostatic force, - \( q_1 \) and \( q_2 \) are the magnitudes of the charges, - \( r \) is the distance between the charges, ...

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The dimensional formula of electric flux is

`[M^(1) L^(2) T^(-2) A^(-1)]`

`[M^(-1) L^(3) T^(-3) A]`

`[M^(1) L^(3) T^(-3) A^(-1)]`

`[M^(1) L^(-3) T^(-3) A^(-1)]`

The value of electric permittivity of free space is

`9xx10 ^(9) N C^(2) m^(-2) `

` 8x85 xx10 ^(-12) N m^(2) C^(-2) `

` 8.85 xx 10^(-12) C^(2) N^(-1) m^(-2) `

` 9xx 10 ^(9) C^(2) N^(-1) m^(-2) `

The dimensional formula of electric potential is

`[ML^(2)T^(-3)A^(1)]`

`[M^(-1)L^(2)T^(-2)A]`

`[M^(-1)L^(2)T^(-2)A^(-1)]`

`[ML^(2)T^(-2)A]`