In Ohm's law experimental verification, the reading of voltage and resistance are `(120 pm 5)V " and "(2 pm 0.1)Omega` respectively. What is the percentage error in the value of current obtained?

Explanation

To find the percentage error in the value of current obtained from Ohm's law, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the given values**:
- Voltage \( V = 120 \pm 5 \, \text{V} \)
- Resistance \( R = 2 \pm 0.1 \, \Omega \)

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