A simple of material having mass 8.89g occupies a volume of `1.9 cm^(3)`. What will be the density of material with correct significant digits?

Options

A. `4.678g"/"c c`
B. `4.6g"/"c c`
C. `4.7g"/"c c`
D. `4.68g"/"c c`

Explanation

To find the density of the material, we can use the formula for density:

\[ \text{Density} (\rho) = \frac{\text{Mass}}{\text{Volume}} \]

### Step 1: Identify the mass and volume
- Mass of the material = 8.89 g
- Volume of the material = 1.9 cm³

### Step 2: Calculate the density
Using the values provided:

\[ \rho = \frac{8.89 \, \text{g}}{1.9 \, \text{cm}^3} \]

### Step 3: Perform the division
Calculating the above expression:

\[ \rho = 4.678947368 \, \text{g/cm}^3 \]

### Step 4: Determine significant figures
Now, we need to consider significant figures in our answer. The mass (8.89 g) has 3 significant figures, while the volume (1.9 cm³) has 2 significant figures. When performing division, the result should have the same number of significant figures as the measurement with the least number of significant figures.

### Step 5: Round the result
Since the volume has 2 significant figures, we round the density to 2 significant figures:

\[ 4.678947368 \approx 4.7 \, \text{g/cm}^3 \]

### Final Answer
Thus, the density of the material, with the correct significant digits, is:

\[ \text{Density} = 4.7 \, \text{g/cm}^3 \]

---