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A vernier calipers has 1mm marks on the ...

A vernier calipers has `1mm `marks on the main scale. It has `20` equal divisions on the Verier scale which match with `16` main scale divisions. For this Vernier calipers, the least count is

A

`0.02 mm`

B

`0.05mm`

C

`0.1mm`

D

`0.2mm`

Text Solution

Verified by Experts

The correct Answer is:
D
Main scale division MSD = 1mm
1 vernier scale division VSD `=(16)/(20)=0.8mm`
Least count is equal to difference between one main scale division and vernier scale division. Hence least count can be written as follows :
`LC= 1MSD - 1VSD= 1-0.8 =0.2 mm`
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Knowledge Check

  • One division on the main scale of a vernier callipers is equal to 1 mm. its vernier scale has 20 equal divisions which match with 16 main scale division. The least countof the vernier calipers is

    A
    0.02 mm
    B
    0.2 mm
    C
    0.8mm
    D
    0.08mm

  • 10 vernier scale divisions VSD match with 9 main scale divisions MSD. Least count of the given vernier caliper is

    A
    `0.1 mm " if "1 MSD = 1mm`
    B
    `0.05 cm " if "1 MSD = 0.05cm`
    C
    `0.01 mm " if "1 MSD = 1mm`
    D
    `0.005 cm " if "1 MSD = 0.05cm`

  • In a vernier callipers n divisions of its main scale match with (n+5) divisions on its vernier scale. Each division of the main scale is of x unit. Using the vernier principle, find the least count.

    A
    `x/(n+5)`
    B
    `(2x)/(n+5)`
    C
    `(5x)/(n+5)`
    D
    `(7x)/(n+5)`