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Check the accuracy of the relation T=2pi...

Check the accuracy of the relation `T=2pisqrt((L)/(g))` for a simple pendulum using dimensional analysis.

Text Solution

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`[t]=[T]`
`[2pi sqrt((l)/(g))]=[(L^(1/2))/(L^(1/2)T^(-1))]=[T]`
The given equation is dimensionally correct.
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