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The diameter of cylinders are d(1)=(2.02...

The diameter of cylinders are `d_(1)=(2.02 pm 0.01)cm " and "d_(2)=(3.21 pm 0.03)cm` respectively. Find the difference between their dimensions along with the error limits.

Text Solution

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`d_(1)=(2.02 pm 0.01)cm, d_(2)=(3.21 pm 0.03)cm`
Difference `d= d_(2)-d_(1)= 3.21-2.02= 1.19cm`
Maximum error in difference, `triangled= pm(triangled_(2)+triangled_(1))= pm (0.03+0.01)`
Difference in diameter `=(1.19 pm 0.04) cm`.
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