Calculate the moment of inertia of an oxygen molecule about an axis passing through its centre of mass and perpendicular to the internuclear axis. Take
Mass of O-atom `=2.67xx10^(-26)kg`
Interatiomic distance `=1.2xx10^(-10)m`

Explanation

To calculate the moment of inertia of an oxygen molecule (O₂) about an axis passing through its center of mass and perpendicular to the internuclear axis, we will follow these steps:

### Step 1: Identify the masses and distances
An oxygen molecule consists of two oxygen atoms. Given:
- Mass of each O-atom, \( m = 2.67 \times 10^{-26} \, \text{kg} \)
- Interatomic distance (internuclear distance), \( d = 1.2 \times 10^{-10} \, \text{m} \)

### Step 2: Determine the center of mass
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