Home
Class 11
PHYSICS
Calculate the angular momentum of earth ...

Calculate the angular momentum of earth rotating about its own axis. Take
Radius of earth `=6.4xx10^(6)m`
Mass of earth `=5.97xx10^(24)kg`

Text Solution

AI Generated Solution

To calculate the angular momentum of the Earth rotating about its own axis, we will follow these steps: ### Step 1: Understand the Formula for Angular Momentum The angular momentum \( L \) of a rotating body can be calculated using the formula: \[ L = I \cdot \omega \] where \( I \) is the moment of inertia and \( \omega \) is the angular velocity. ...
Promotional Banner

Topper's Solved these Questions

  • SYSTEMS OF PARTICLES AND ROTATIONAL MOTION

    MODERN PUBLICATION|Exercise PRACTICE PROBLEMS|26 Videos
  • SYSTEMS OF PARTICLES AND ROTATIONAL MOTION

    MODERN PUBLICATION|Exercise Conceptual Questions|24 Videos
  • PHYSICAL WORLD

    MODERN PUBLICATION|Exercise Revision exercises (Long answer questions)|6 Videos
  • THERMAL PROPERTIES OF MATTER

    MODERN PUBLICATION|Exercise CHAPTER PRACTICE TEST|15 Videos

Similar Questions

Explore conceptually related problems

The value of angular momentum of the earth rotating about its own axis is

Calculate the angular momentum of the earth rotating about its own axis. Mass of the earth = 5.98 xx 10^(27) kg, mean radius of the earth =6.37 xx 10^(6)m,M.I of the earth = (2)/(5)MR^(2) .

Calculate angular momentum of earth rotating about its axis. Take I = (2)/(5)MR^(2) , where M = 6 xx 10^(24) kg and R = 6400 Km .

A satellite revolves around the earth at a height of 1000 km. The radius of the earth is 6.38 xx 10^(3) km. Mass of the earth is 6xx10^(24)kg and G=6.67xx10^(-14)"N-m"^(2)kg^(-2) . Determine its orbital velocity and period of revolution.

An artificial satellite revolves round the earth at a height of 1000 km . The radius of the earth is 6.38xx10^(3)km . Mass of the earth 6xx10^(24)kg,G=6.67xx10^(-11)Nm^(2)kg^(-2) . Find the orbital speed and period of revolution of the satellite.

A mango of mass 0.3 kg falls from a tree. Calculate the acceleration of the mango towards the earth. Also calculate the acceleration of the earth towards the mango. Take, Mass of the earth = 5.983 xx 10^(24) kg Radius of the earth = 6.378 xx 10^(6) m G = 6.67 xx 10^(-11) Nm^(2) kg^(-2)

An apple of mass 0.25 kg falls from a tree . What is the acceleration of the apple towards the earth ? Also calculate the acceleration of the earth towards the apple . Mass of the earth = 5.983 xx 10^(24) kg , Radius of the earth = 6.378 xx 10^(6) m and G = 6.67 xx 10^(-11)Nm^(2) kg^(-2)

The value of 'g' on the surface of the earth is 9.81 ms^(-2) . Find its value on the surface of the moon . Given mass of earth 6.4 xx 10^(24) kg , radius of earth = 6.4 xx 10^(6) m , mass of the moon = 7.4 xx 10^(22) kg , radius of moon = 1.76 xx 10^(6) m .

A satellite of mass 2xx10^(3)kg has to be shifted from an orbit of radius 2R to another of radius 3R, where R is the radius of the earth. Calculate the minimum energy required. Take mass of earth =6xx10^(24)kg , radius of earth =6.4xx10^(6)m .

Calculate rotational K.E. of earth about its own axis, taking it to be a sphere of mass 6 xx 10^(24) kg and radius 6400 km .

MODERN PUBLICATION-SYSTEMS OF PARTICLES AND ROTATIONAL MOTION-Chapter Practice Test (for Board Examination)
  1. Calculate the angular momentum of earth rotating about its own axis. T...

    Text Solution

    |

  2. Can centre of mass of a body lie where there is absolutely no mass ?

    Text Solution

    |

  3. Which component of linear momentum does not contribute to angular mome...

    Text Solution

    |

  4. Can a body moving in a circular path be at equilibrium?

    Text Solution

    |

  5. Does the moment of inertia of a body change with the speed of rotatio...

    Text Solution

    |

  6. Two lenses, one convex and other concave, are of same mass and same ra...

    Text Solution

    |

  7. Why the handles of the doors are at maximum distance from the hinges?

    Text Solution

    |

  8. State and explain parallel axis theorem and perpendicular axis theorem...

    Text Solution

    |

  9. If earth were to shrink suddenly, what would happen to the length of t...

    Text Solution

    |

  10. The angular momenta of two bodies X and Y are equal and moment of iner...

    Text Solution

    |

  11. (i) A person sits near the edge of a circular platform revolving with ...

    Text Solution

    |

  12. Show that the angular momentum of a particle is equal to twice the pro...

    Text Solution

    |

  13. Establish a relation between angular momentum and moment of inertia of...

    Text Solution

    |

  14. Write the relation between electric power (W ) of a device with potent...

    Text Solution

    |

  15. How will you distinguish between a hard boiled egg and a raw egg by s...

    Text Solution

    |

  16. The speed of the motor of an engine is 300 rpm. In 2 s, the speed incr...

    Text Solution

    |

  17. Derive an expression for the acceleration of a solid cylinder rolling ...

    Text Solution

    |