Determine the moment of inertia of a wheel rotating at a rate of 1200 rpm about its axis of rotation. Given that the kinetic energy of the wheel is `3xx10^(6)J`.

Explanation

To determine the moment of inertia (I) of a wheel rotating at a rate of 1200 rpm with a kinetic energy (KE) of \(3 \times 10^6 \, J\), we can follow these steps:

### Step 1: Convert angular velocity from rpm to rad/s
The angular velocity in radians per second can be calculated using the formula:
\[ \omega = \text{rpm} \times \frac{2\pi}{60} \]
Substituting the given value:
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