Home
Class 11
PHYSICS
Two charged particles of masses m and 2m...

Two charged particles of masses m and 2m are placed distane d apart on a smooth horizontal table. Because of their mutual attraction, they move towards each other and collide. Where will the collision occure with respect to the initial positions?

Text Solution

Verified by Experts

If we consider both the particles in a single system then electric force of attraction becomes internal force of the system and there is no other force acting on this system in horizontal direction. Hence ncceleration of centre of mass of the system is zero in the horizontal direction. Particles are released from the state of rest hence initial velocity of the centre of mass is vero. As we have understood that initial velocity of the centre of Mass is zero and acceleration is also zero in the horizontal direction hence centre of mass remains at rest during the process. So finally both the particles will collide at the initial location of centre of mass. Initial distance of centre of mass from m can be calculated as follows:
`x=(mxx0+2mxxd)/(m+2m=(2d)/(3)`
So we can understand that collision between particles occurs at a distance 2d/3 from initial position of particle of mass m.
Promotional Banner

Topper's Solved these Questions

  • SYSTEMS OF PARTICLES AND ROTATIONAL MOTION

    MODERN PUBLICATION|Exercise REVISION EXERCISES (Very Short Answer Questions Carrying 1 mark)|29 Videos

  • SYSTEMS OF PARTICLES AND ROTATIONAL MOTION

    MODERN PUBLICATION|Exercise REVISION EXERCISES (Additional Questions Carrying 1 mark )|4 Videos

  • SYSTEMS OF PARTICLES AND ROTATIONAL MOTION

    MODERN PUBLICATION|Exercise NCERT FILE (NCERT EXEMPLAR PROBLEMS (SUBJECTIVES QUESTIONS) (Very Short Answer Type Questions))|9 Videos

  • PHYSICAL WORLD

    MODERN PUBLICATION|Exercise Revision exercises (Long answer questions)|6 Videos

  • THERMAL PROPERTIES OF MATTER

    MODERN PUBLICATION|Exercise CHAPTER PRACTICE TEST|15 Videos

Similar Questions

Explore conceptually related problems

Two particles of mass M and 2M are at a distance D apart. Under their mutual force of attraction they start moving towards each other. The acceleration of their centre of mass when they are D/2 apart is :

Two particles of masses 4kg and 6kg are separated by a distance of 20cm and are moving towards each other under mutual force of attraction, the position of the point where they meet is

Two particles A and B of masses 2m and m are placed on a smooth surface at separation d . They move towards each other due to the mutual attractive force. (i) The particles will meet at distance d//3 from the initial position of mass 2m . (ii) The speed of A will be half of speed of B until the particles collide (excluding the initial speed). (iii) The distance covered by B is always double that covered by A until the particles collide. (iv) The velocity of center of mass is always zero.

Two particles each of mass M and equidistant from each other move along a circle of radius R under the action of their mutual gravitional attraction the speed of each particle is

Two particles of masses 2m and 3m are placed at separation d on a smooth surface. They move towards each other due to mutual attractive force. Find (a) acceleration of c.m. (b) Velocity of c.m. when separation between particles becomes d//3 . ( c) At what distance from the initial position of mass 2m , the particles collide.

Two spheres of masses 2M and M are initially at rest at a distance R apart. Due to mutual force of attraction, they approach each other. When they are at separation R//2 , the acceleration of the centre of mass of spheres would be

A particle of mass m moving with a speed v hits elastically another staionary particle of mass 2m on a smooth horizontal circular tube of radius r . Find the time when the next collision will take place?

Two particles of equal mass (m) each move in a circle of radius (r) under the action of their mutual gravitational attraction find the speed of each particle.

Two particles of equel mass (m) move in a circle of radius (r ) under the action of their mutual gravitational attraction.Find the speed of each particle.

Two particles of mass m and M are initially at rest and infinitely separated from each other. Due to mutual interaction, they approach each other. Their relative velocity of approach at a separation d between them, is

Knowledge Check

  • Two particles of mass M and 2M are at a distance D apart. Under their mutual force of attraction they start moving towards each other. The acceleration of their centre of mass when they are D/2 apart is :

    A
    `2 GM//D^(2)`
    B
    `4 GM//D^(2)`
    C
    `8 GM//D^(2)`
    D
    Zero

  • Two particles of masses 4kg and 6kg are separated by a distance of 20cm and are moving towards each other under mutual force of attraction, the position of the point where they meet is

    A
    `12 m`from `4kg` body
    B
    `12 m` from `6 kg` body
    C
    `8m` from `4 kg` body
    D
    `10 m` from `4 kg` body

  • Two particles A and B of masses 2m and m are placed on a smooth surface at separation d . They move towards each other due to the mutual attractive force. (i) The particles will meet at distance d//3 from the initial position of mass 2m . (ii) The speed of A will be half of speed of B until the particles collide (excluding the initial speed). (iii) The distance covered by B is always double that covered by A until the particles collide. (iv) The velocity of center of mass is always zero.

    A
    `(i) ,(ii)`
    B
    `(i),(ii),(iii)`
    C
    `(ii),(iii),(iv)`
    D
    all options are correct