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Two particles having masses of 2 kg and ...

Two particles having masses of 2 kg and 3 kg are moving along the same straight line with velocities of `3 ms^(-1) and 6 ms^(-1)` respectively. Calculate the speed of centre of mass of system if particles are moving in
(a) same direction. (b) in opposite direction.

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To solve the problem of finding the speed of the center of mass of two particles with given masses and velocities, we will follow these steps: ### Given Data: - Mass of particle 1 (m1) = 2 kg - Velocity of particle 1 (v1) = 3 m/s - Mass of particle 2 (m2) = 3 kg - Velocity of particle 2 (v2) = 6 m/s ...
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Knowledge Check

  • Two particles of mass 1 kg and 0.5 kg are moving in the same direction with speed of 2 m//s and 6 m/s respectively on a smooth horizontal surface. The speed of centre of mass of the system is

    A
    `(10)/(3) m//s`
    B
    `(10)/(7) m//s`
    C
    `(11)/(2) m//s`
    D
    `(12)/(3) m//s`

  • Two particles A and B of masses 10 kg and 38 kg, respectively, are moving along the same straight line with velocities 15 m/s and 3 m/s, respectively, in the same direction. After elastic collision, the velocities of A and B are v_A and v_B , respectively, in the direction of initial motion. Then

    A
    `v_A = 20 m//s, v_B = 8 m/s `
    B
    `v_A = – 4 m//s, v_B = 8 m//s`
    C
    `v_A = 16 m/s, v_B = 28 m//s`
    D
    `v_A = – 5 m//s, v_B = 10 m//s`

  • Two particles of masses 2 kg and 4 kg are approaching each other with acceleration 1 ms^(-2) and 2 ms^(-2) , respectively, on a smooth horizontal surface. Find the acceleration of center of mass of the system.

    A
    `1`
    B
    `2`
    C
    `3`
    D
    `4`
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