A torque `tau` applied to a dise of mass 2 kg and radius of gyration 15 cm produces an angular acceleration of `5 "rad"//sec^(2)`. Find the value of `tau`.

Explanation

To find the value of the torque \( \tau \) applied to the disk, we can follow these steps:

### Step 1: Understand the relationship between torque, moment of inertia, and angular acceleration.
The torque \( \tau \) is related to the moment of inertia \( I \) and angular acceleration \( \alpha \) by the equation:
\[ \tau = I \cdot \alpha \]

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