A circular ring rotating about an axis passing through its centre and perpendicular to its plane is making 300 revolutions/min. What will be the kinetic energy of rotation of the ring if mass of ring is 0.3 kg and radius 0.4 m.

Explanation

To find the kinetic energy of rotation of the ring, we will use the formula for rotational kinetic energy:

\[ K.E. = \frac{1}{2} I \omega^2 \]

where \( I \) is the moment of inertia and \( \omega \) is the angular velocity in radians per second.

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