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Consider a cylinder of mass M resting on...

Consider a cylinder of mass M resting on a rough horizontal rug that is pulled out from under it with acceleration 'a' perpendicular to the axis of the cylinder. What is `F_("friction")` at point P? It is assumed that the cylinder does not slip.

A

`Mg`

B

`Ma`

C

`(Ma)/(2)`

D

`(Ma)/(3)`

Text Solution

Verified by Experts

The correct Answer is:
D
Force of friction acting at point P,
`F_("friction")=(1)/(3)Masintheta`
`=(1)/(3)Masin90^(@)" "["here"theta=90^(@)]`
`=(Ma)/(3)`
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