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The coordinates of a particle of mass 'm...

The coordinates of a particle of mass `'m'` as function of time are given by `x=x_(0)+a_(1) cos(omegat)` and `y=y_(0)+a_(2)sin(omega_(2)t)`. The torque on particle about origin at time `t=0` is :

A

`m(-x_(0)b+y_(0)a) omega_(1)^(2)hatk`

B

`my_(0) a omega_(1)(2) hatk`

C

Zero

D

`-m(x_(0)b omega_(2)^(2)-y_(0)a omega_(1)^(2)) hatk`

Text Solution

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The correct Answer is:
B
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