Derive an expression for the acceleration of a solid cylinder rolling without slipping down an inclined plane. Also find the minimum coefficient of friction required for pure rolling

Explanation

`v_(0)=300r"pm"=(300)/(60)rps`
`omega_(0)=(2pixx300)/(60)=10pi,v=420r"pm"=(400)/(60)rps`
`omega=(2pixx420)/(60)=14pi`
As `omega=omega_(2)+alphat`
`14pi=10pi+alphaxx2`
`alpha=2pirad//sec^(2)`
As `theta=omega_(0)t+(1)/(2)alphat^(2)`
`=10pixx2+(1)/(2)xx2pixx(2)^(2)`
`=20pi+4pi=24pi`
No. of revolution completed `=(theta)/(2pi)=(24pi)/(2pi)=12`