Home
Class 11
PHYSICS
A faulty constant volume thermometer usi...

A faulty constant volume thermometer using helium gas records a pressure of `1.65 xx 10^4` Pa at normal freezing point of water, and a pressure of `2.10 xx 10^4` Pa at normal boiling point of water. Using these observations, determine the temperature of absolute zero on the Celsius scale.

Text Solution

AI Generated Solution

To determine the temperature of absolute zero on the Celsius scale using the given pressures from a faulty constant volume thermometer with helium gas, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Values**: - Pressure at freezing point (P1) = \(1.65 \times 10^4 \, \text{Pa}\) - Pressure at boiling point (P2) = \(2.10 \times 10^4 \, \text{Pa}\) - Freezing point of water (T1) = \(0^\circ \text{C}\) ...
Promotional Banner

Topper's Solved these Questions

  • THERMAL PROPERTIES OF MATTER

    MODERN PUBLICATION|Exercise PRACTICE PROBLEM|28 Videos
  • THERMAL PROPERTIES OF MATTER

    MODERN PUBLICATION|Exercise CONCEPTUAL QUESTIONS|16 Videos
  • SYSTEMS OF PARTICLES AND ROTATIONAL MOTION

    MODERN PUBLICATION|Exercise Chapter Practice Test (for Board Examination)|16 Videos
  • UNITS AND MEASUREMENT

    MODERN PUBLICATION|Exercise CHAPTER PRACTICE TEST|15 Videos

Similar Questions

Explore conceptually related problems

A constant volume thermometer using helium gas records a pressure of 1.75 xx 10^4 Pa at normal freezing point of water, and a pressure of 2.39 xx 10^4 Pa at normal boiling point of water. Obtain from these observations the temperature of absolute zero on the Celsius scale.

A constant volume thermometer registers o pressure of 1.500 xx 10^4 Pa at the triple point of water and a pressure of 1.500 xx 10^4 Pa at the normal boiling point. What is the temperature at the normal boiling point?

A constant volume gas thermometer using Sulphur records a pressure of 2xx10^4 Pa at the triple point of water and 2.87xx10^4 Pa at temperature of melting Sulphur. Calculate the melting point of Sulphur.

A constant volume gas thermometer using helium records a pressure of 20.0 kPa at the triple-point of water, and pressure of 14.3 kPa at the temperature of 'dry ice' (solid CO_(2) ). What is the temperature of 'dry ice' ?

The pressure recorded by a constant volume gas thermometer is 3.1 xx10^4 Pa at melting point of sulphur and 1.8 xx 10^4 Pa at triple point of water. What will be melting point of sulphur?

The pressure measured by a constant volume gas thermometer is 40 kPs at the triple point of water. What will be the pressure measured at the boiling point of water (100^ C) ?

A glass container encloses a gas a pressure of 8 xx 10^(5) pa and 300 K temperature. The container walls can bear a maximum pressure of 10^(6) Pa. If the temperature of container is gradually increased, find the temperature at which the container will break.

A glass container encloses gas at a pressure 4 xx10^5 Pa and 300 K temperature. The container walls can bear a maximum pressure of 8 xx10^(5) Pa. If the temperature of container is gradually increased find temperature at which container will break.

A vessel contains a gas under a pressure of 5 xx 10^(5)pa . If 3//5 of the mass of the gas is flown out, What will be the gas pressure if the temperature being maintained constant,

The presssure of the gas in a constant volume gas thermometer at steam point (373.15K) is 1.50 xx 10^4 Pa . What will be the pressure of the triple point of water?