A thermally isolated vessel is maintained inside at `0^@C` and contains 200 g of water. When the air above the water is pumped out, some of the water freezes while rest of it evaporated at `0^@C` itself. Determine the mass of water that freezed. Take, Latent heat of vapourisation of water at `0^@C = 2.19 xx 10^3 J//g`
Latent heat of fusion of ice =` 3.36 xx 10^2 J//g`

Explanation

To solve the problem, we need to analyze the energy exchanges that occur when some of the water freezes and some evaporates in a thermally isolated vessel.

### Step-by-Step Solution:

1. **Identify the Variables**:
- Let \( m \) be the mass of water that freezes (in grams).
- The total mass of water is given as \( 200 \, \text{g} \).
- Therefore, the mass of water that evaporates is \( 200 - m \).
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