In a container containing 0.2 kg of water at `40^@C` , 0.2 kg of ice at `0^@C` is mixed. Calculate the heat of fusion of ice if the resulting temperature is `5.5^@C` . Take, Specific heat of water = `4186 J kg^(-1)K^(-1)`

Explanation

To solve the problem, we will use the principle of conservation of energy, which states that the heat lost by the warm water will be equal to the heat gained by the ice and the water formed from the ice.

### Step-by-Step Solution:

1. **Identify the known values:**
- Mass of water, \( m_w = 0.2 \, \text{kg} \)
- Initial temperature of water, \( T_{w_i} = 40^\circ C \)
- Mass of ice, \( m_i = 0.2 \, \text{kg} \)
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