In a certain arrangement, two cylinders of brass and steel are laid side by side and there is a constant difference of length between them at any temperature. Calculate the lengths of these cylinders at `0^@C` if there is a difference of 5 cm between their lengths at all temperatures.
`alpha_("brass") = 0.0000019^@C^(-1)`
` alpha_("steel") = 1.2 xx 10^(-6) C^(-1)`

Explanation

To solve the problem, we need to find the lengths of the brass and steel cylinders at 0°C given that there is a constant difference of 5 cm between their lengths at all temperatures. We will use the linear expansion formula for solids, which states that the change in length (ΔL) of a material due to a change in temperature (ΔT) is given by:

\[ \Delta L = L_0 \alpha \Delta T \]

where:
- \(L_0\) is the original length,
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