A clock with a steel pendulum gives accurate time at `30^@C` . Calculate the fractional loss or gain in time if temperature changes to `50^@C` . Coefficient of linear expansion of steel `= 12 xx 10^(-6) ""^@C^(-1)`

Explanation

To solve the problem of calculating the fractional loss or gain in time for a clock with a steel pendulum when the temperature changes from \(30^\circ C\) to \(50^\circ C\), we will follow these steps:

### Step 1: Identify the change in temperature
The initial temperature \(T_1 = 30^\circ C\) and the final temperature \(T_2 = 50^\circ C\).
The change in temperature \(\Delta T\) can be calculated as:
\[ \Delta T = T_2 - T_1 = 50^\circ C - 30^\circ C = 20^\circ C \]
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