A body cools from `90^@C` to `80^@C` in 2 minutes. How long will it take to cool from `70^@C` to `50^@C` if temperature of surroundings is `16^@C` ?

Explanation

To solve the problem, we will use Newton's Law of Cooling, which states that the rate of change of temperature of an object is proportional to the difference between its temperature and the ambient temperature.

### Step-by-step Solution:

1. **Identify the given values:**
- Initial temperature (T1) = 90°C
- Final temperature (T2) = 80°C
- Time taken (t1) = 2 minutes
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