The initial temperature of a black body is `527^@C`. What should be its temperature so as to double the emitted radiations?

Explanation

To solve the problem of finding the temperature at which the emitted radiation from a black body doubles, we can use the Stefan-Boltzmann Law. This law states that the power emitted per unit area of a black body is proportional to the fourth power of its absolute temperature (in Kelvin).

### Step-by-Step Solution:

1. **Convert Initial Temperature to Kelvin:**
The initial temperature of the black body is given as \( 527^\circ C \). To convert this to Kelvin, we use the formula:
\[
T_1 = 527 + 273.15 = 800.15 \, K
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