A metallic cylindrical shell of length 50 cm has inner radius of 3 cm and outer radius of 6 cm. If the inner and outer surfaces of the cylinder are maintained at `0^@C` and `80^@C` , respectively, then find the rate of flow of heat from the outer surface to the inner surface. Take, thermal conductivity of metal `= 69.3 Wm^(-1) k^(-1) `

Explanation

To find the rate of heat flow from the outer surface to the inner surface of a metallic cylindrical shell, we can use the formula for heat conduction through a cylindrical shell. The formula is given by:

\[ \frac{dQ}{dt} = \frac{2 \pi k L (T_2 - T_1)}{\ln\left(\frac{R_2}{R_1}\right)} \]

Where:
- \( \frac{dQ}{dt} \) is the rate of heat flow (in Watts),
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