A copper block of mass `2.5 kg` is heated in a furnace to a temperature of `500^(@)C` and then placed on a large ice block. What is the maximum amount (approx.) of ice that can melt? (Specific heat copper `= 0.39 J//g^(@)C` heat of fusion of water `= 335 J//g`).

Explanation

Mass of copper block, m = 2.5 kg = 2500 g
Temperature change of copper block = `Delta T = 500^@C`
Specific heat of copper, `C = 0.39 Jg^(-1) C^(-1)`
Heat content of copper = `Delta Q`
` = 2500 xx 0.39 xx 10^3 xx 500 J`
Latent heat of fusion of water,` L = 335 Jg^(-1)`.
` = 335 xx 10^3 J kg^(-1)`
m. = amount of ice melted
Heat gained by ice = Heat lost by water
`m. L = mc Delta T`
Mass of ice melted (m.) `= ((2500 xx 0.39 xx 1)3 xx 500)/(335 xx 10^3)`
= 15kg