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A cubical icebox made of thermocol of th...

A cubical icebox made of thermocol of thickness 4 cm has each side equal to 20 cm. An ice block of mass 500 g is placed inside the box. If the box is suspended in a room at `50^@C` , what will be the approximate mass of unmelted ice left in 2 hours? Take, coefficient of thermal conductivity of thermocol ` = 10^(-2) Wm^(-1) K^(-1)`
Latent heat of fusion of water `= 3.35 xx 10^5 J kg^(-1)`

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To solve the problem step by step, we need to calculate the amount of heat transferred from the room to the ice inside the thermocol icebox and then determine how much ice melts as a result of this heat transfer. ### Step 1: Calculate the surface area of the icebox The icebox is cubical with each side measuring 20 cm (0.2 m). The surface area \( A \) of a cube is given by: \[ A = 6a^2 \] where \( a \) is the length of one side. ...
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